[" Equation of a particle moving along the x axis is "],[x=u(t-2)+a(t-2)^(2)]

A particle moves along the X-axis as x=u(t-2s)+a(t-2s)^2 .

A particle moves along the X-axis as x=u(t-2s)=at(t-2)^2 .

A particle moves along the X-axis as x=u(t-2s)=at(t-2)^2 .

A particle moves along the X-axis as x=u(t-2 s)+a(t-2 s)^2 .

A particle moves along the X-axis as x=u(t-2 s)+a(t-2 s)^2 .

The displacement -time equation of a particle moving along x -axis is x=(t^(3))/(3)-(t^(2))/(2)+20 The acceleration -velocity equation of the particle is a^(2)=KV+1 Then the value of K is

[" Position of particle "],[" moving along x axis is "],[" given by "x=t^(3)+4t+2" .Here "x],[" is in metre and "t" is in "],[" seconds.Find "],[" displacement of particle "],[" from "t=2" to "t=4" sec."]

The position of particle moving along the x-axis veries with time t as x=6t-t^(2)+4 . Find the time-interval during which the particle is moving along the positive x-direction.

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is