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" ाना "I=int(1)/(sin(x-a)sin(x-b))...

" ाना "I=int(1)/(sin(x-a)sin(x-b))

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int (1)/(sin(x-a)sin (x-b))dx=

int (dx)/(sin(x-a)sin(x-b)

int (dx)/(sin(x-a)sin(x-b)) is

int(dx)/(sin(x+a)sin(x+b))=

int dx/(sin(x-a)sin(x-b)) =

I=int(1)/(cos(x+a)sin(x+b))dx

I=int(sin(x+a))/(sin(x-a))dx

Evaluate: int(1)/(sin(x-a)sin(x-b))dx

Evaluate: int(1)/(sin(x-a)sin(x-b))dx