If `cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma`, then `(sin3alpha+sin3beta+sin3gamma)/(sin(alpha+beta+gamma))` is equal to

If cos alpha+ cos beta + cos gamma = sin alpha+ sin beta +sin gamma= 0 , then :

If sin alpha+ sin beta+ sin gamma=3, then sin^3alpha+sin^3beta+sin^3 gamma=

If cos alpha + cos beta + cos gamma = 3 then sin alpha + sin beta + sin gamma =

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma then x^(sin(2 alpha-beta-gamma)*x^(sin(2 beta-gamma-alpha)))*x ^(sin(2 gamma-alpha-beta)) is

If cos alpha + cos beta + cos gamma = sin alpha + sin beta + sin gamma = 0 , show that sin 3alpha + sin 3 beta + sin 3gamma = 3 sin (alpha + beta + gamma)

If cos alpha+cos beta+cos gamma=0 and also sin alpha+sin beta+sin gamma=0 then prove that

If cos alpha+cos beta+cos gamma=0 & sin alpha +sin beta +sin gamma=0 . Then Prove that sin2alpha+sin2beta+sin2gamma=0

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then show that sin 3 alpha + sin 3 beta + sin 3 gamma = 3 sin ( alpha + beta + gamma)