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[" For any "theta in((pi)/(4),(pi)/(2))," the expression ",[" (b) "2],[" (b) "2sin2],[" (c) "4]],[3(sin theta-cos theta)^(4)+6(sin theta+cos theta)^(2)+4sin^(6)theta" equals "],[" (2019Main,9Jan I) "]

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For any theta epsilon((pi)/4,(pi)/2) the expression 3(sin theta-cos theta)^(4)+6(sin theta+cos theta)^(2)+4sin^(6)theta equals:

For any theta epsilon((pi)/4,(pi)/2) the expression 3(sin theta-cos theta)^(4)+6(sin theta+cos theta)^(2)+4sin^(6)theta equals:

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int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

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2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to

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