" 170.(i) "(dx)/(e^(x)-1)

Evaluate (i) int_(0)^(1) (dx)/(e^(x)+e^(-x))

I=int(e^x)/(e^(x)-1)dx

"I=int(dx)/(1+e^(x))

Evaluate: (i) int(1)/(e^(x)+1)dx (ii) int(cot x)/(log sin x)dx

(i) int (dx)/(e^x+e^(-x)) (ii) int e^x/(e^(2x)+1) dx

The differentiation of e^(x) with respect to x is e^(x). i.e.(d)/(dx)(e^(x))=e^(x)

Evaluate: (i) int(e^(x)+1)/(e^(x)+x)dx( ii) int(1)/(x log x)dx

If f(x) =(e^(x))/(1+e^(x)),I_(1)=overset(f(a))underset(f(-a))int xg{x(1-x)}dx and I_(2)=overset(f(a))underset(f(-a))int g{x(1-x)}dx , where g is not identify function. Then the value of I_(2)//I_(1) , is