The potential energy function of a particle is given by `U(r)=A/(2r^(2))-B/(3r)`, where `A` and `B` are constant and `r` is the radial distance from the centre of the force. Choose the correct option (s)

The potential energy of a particle in a force field is: U = (A)/(r^(2)) - (B)/(r ) ,. Where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium the distance of the particle is

The potential energy of a particle in a force field is: U = (A)/(r^(2)) - (B)/(r ) ,. Where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium the distance of the particle is

The potential energy of a particle in a certain field has the form U=(a//r^2)-(b//r) , where a and b are positive constants and r is the distance from the centre of the field. Find the value of r_0 corresponding to the equilibrium position of the particle, examine whether this position is stable.

The potential energy of a particle in a certain field has the form U=(a//r^2)-(b//r) , where a and b are positive constants and r is the distance from the centre of the field. Find the value of r_0 corresponding to the equilibrium position of the particle, examine whether this position is stable.