If internal resistance of cell is negligible, then current flowing through the circuit is

Two cells having emf's of 10 V and 8 V, and internal resistance of 1Omega (each) are connected as shown with an external resistance of 8Omega Find the current flowing through the circuit.

Two cells having emf's of 10 V and 8 V, and internal resistance of 1Omega (each) are connected as shown with an external resistance of 8Omega Find the current flowing through the circuit.

The cells of emf's E_(1) and E_(2) be connector in parallel in a circuit. Let r_(1) and r_(2) be the internal resistance of the cells. Then the current through the circuit is

A battery of unknown emf and internal resistance is given to a student for the experiment. When student connects the battery to an external resistance of 10 Omega then 1A current flows through the circuit and when the same is connected to 15 Omega resistance then 0.75 A current flows through the circuit . Calculate the emf and internal resistance of the given battery.

A resistance of 1 Omega is connected to a battery of emf 2 V and internal resistance 0.4 Omega what current is flowing through the circuit ? If another battery of double the emf is connected in series with the earlier one then current flowing in the circuit becomes double . what should be the internal resistance of battery ?

When 'n' number of identical cells, each of emf E and internal resistance r are grouped in series, the current flowing through an external resistance R is given by

The current flowing through the cell in the circuit shown is

The current flowing through the cell in the circuit shown is