[" Prove that the two parabolas "y^(2)=" tax and "x^(2)=4by" intersect (ot "],[tan^(-1)((3a^(x)b^(7))/(2(a^(7)+b^(7)))]

Prove that the two parabolas y^(2)=4ax and x^(2)=4by intersects at an angle of tan^(1)[(3a^((1)/(3))b^((1)/(3)))/(2(a^((2)/(3))+b^((2)/(3))))]

Prove that two parabolas y_(2)=4ax "and" x^(2)=4by intersect (other than the origin ) at an angle of Tan^(-1)[(3a^(1//3)b^(1//3))/(2(a^(2//3)+b^(2//3)))] .

Vertex of the parabola x ^(2) +4x + 2y -7=0 is

Vertex of the parabola x ^(2) +4x + 2y -7=0 is

Prove that 2 tan^(-1) ((3)/(4)) = tan^(-1) ((24)/(7))

Prove that the normals at the points (1,2) and (4,4) of the parabola y^(2)=4x intersect on the parabola

The vertex of the parabola x^2-2x-4y-7=0 , is:

Consider the parabola y=x^(2)+7x+2 and the straight line y=3x-3 . The two parabolas y^(2)=4ax" and "x^(2)=4ay intersect

prove that: 2 tan ^(-1)x =(1)/(3) tan^(-1).(1)/( 7) = (pi)/(4)

The focus of the parabola y^(2) + 6x - 2y + 13 = 0 is at the point a) ((7)/(2), 1) b) ((-1)/(2),1) c) (-2,(1)/(2)) d) (-(7)/(2),1)