[" If "int(cos x-sin x+1-x)/(e^(x)+sin x+x)dx=ln(f(x))+g(x)+c" where "C" is the constant of im "],[f(x)" is positive,then "f(x)+g(x)" has the yalue equal to "]

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

If int(x(sin x-cos x)-sin x)/(e^(x)+(sin x)x)dx=-ln(f(x))+g(x)+C where C is the constant of integration and f(x) is positive then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. The f(x)+g(x) has the value equal to a) e^(x)+sinx+2x b) e^(x)+sinx c) e^(x)-sinx d) e^(x)+sinx+x

If int (cos x-sin x + 1-x)/(e^(x)+sin x+x)dx=ln{f(x)}+g(x)+C , where C is the constant of integrating and f(x) is positive, then (f(x)+g(x))/(e^(x)+sin x) is equal to .......... .

int(cos x-sin x+1-x)/(e^(x)+sin x+x)dx=ln(f(x))+g(x)+c where e^(x)+sin x+x positive,then f(x)+g(x) has the value equal to

if int f (x ) sin x cos x dx = (1)/(2(b^(2) -a^(2)) log f(x ) + c where C is a constant of intergration then f(x) =

int(x(sin x+cos x)+cos x)/(e^(-x)+x sin x+cos x)dx=f(x)+log|g(x)|+c then f(x)+g(x)=