Calculate the enthalpy of solution of sodium chloride. The lattice energy of `NaCl` is `+186 kcal mol^(-1)`. And the solution enthalpies of cations and anions are respectively `-97` and `-85 kcal mol^(-1)`

Calculate the enthalpy of formation of aniline. The enthalpy of combustion of aniline is 837.5 kcal mol^(-1) . The enthalpies of formation of liquid water and gaseous carbon dioxide are -68.4 and -97.0kcal mol^(-1) respectively. All values are at 298 K .

Calculate the enthalpy of formation of aniline. The enthalpy of combustion of aniline is 837.5 kcal mol^(-1) . The enthalpies of formation of liquid water and gaseous carbon dioxide are -68.4 and -97.0kcal mol^(-1) respectively. All values are at 298 K .

The enthalpy of solution of sodium chloride is 4 kJ mol^(-1) and its enthalpy of hydration of ion is -784 kJ mol^(-1) . Then the lattice enthalpy of NaCl (in kJ mol^(-1) ) is

The enthalpy of solution of sodium chloride is 4 kJ mol^(-1) and its enthalpy of hydration of ion is -784 kJ mol^(-1) . Then the lattice enthalpy of NaCl (in kJ mol^(-1) ) is

If enthalpy of formation of "CCl_4 is 316 kcal mol^(-1) the dissociation energy of C-Cl is

For NaCl , lattice energy = - 186 kcal//mol , the solvation energy of Na^(+) and Cl are -97 and -85 kcal//"mole" respectively. Therefore for NaCl (s)

The lattice energy of solid KCl is 181 kcal mol^(-1) and the enthalpy of solution of KCl in H_(2)O is 1.0 kcal mol^(-1) . If the hydration enthalpies of K^(o+) and Cl^(Theta) ions are in the ratio of 2:1 then the enthalpy of hydration of K^(o+) is -20xK cal mol^(-1) . Find the value of x .