The normal form of 2x – 2y +z = 5 is

Find the normal form of the plane 2x+3y-z = 5 . Also find the length of perpendicular from origin and d.c's of the normal to the plane.

Find the normal form of the plane 2x+3y-z = 5 . Also find the length of perpendicular from origin and d.c's of the normal to the plane.

Normal form of x+y+sqrt(2)=0 is

Write the normal form of the equation of the plane 2x-3y+6z+14=0.

Write the normal form of the equation of the plane 2x-3y+6z+14=0.

The directions cosines of the normal to the plane 2x-y +2z =3 are

The d.c.'s of the normal to the plane 2x + 3y – 6z + 5 = 0 are

The planes : 2x – y + 4z = 5 and 5x – 2.5 y + 10 z = 6 are