In a `triangle ABC` the sides `BC=5, CA=4` and `AB=3`. If `A(0,0)` and the internal bisector of angle A meets BC in D `(12/7,12/7)` then incenter of `triangle ABC` is

In a /_ABC the sides BC=5,CA=4 and AB=3. If A(0,0) and the internal bisector of angle A meets BC in D((12)/(7),(12)/(7)) then incenter of /_ABC is

In a triangle ABC , AB = AC and angle A = 36^(@) If the internal bisector of angle C meets AB at D . Prove that AD = BC.

Draw a triangle ABC of base BC=5.6 cm, angle A=40^(@) and the bisector of angle A meets BC at D such that CD=4 cm.

Draw a triangle ABC of base BC = 5.6 cm, angle A = 40^(@) and the bisector of angle A meets BC at D such that CD = 4 cm .

In a Delta ABC,AD is the bisector of the angle A meeting BC at D.If I is the in centre of the triangle,then AI:DI is equal to

Given a triangle ABC with AB= 2 and AC=1 . Internal bisector of angleBAC intersects BC at D. If AD = BD and Delta is the area of triangle ABC, then find the value of 12Delta^2 .

In Delta ABC , internal angle bisector of angle A meets side BC in D. DE bot AD meets AC in E and AB in F. Then

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .