The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of `._2^4He` , if mass of `._2^4He ` is 4.0015 u is

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u= atomic mass unit). The binding energy of ._(2)He^(4) is (mass of helium nucleus =4.0015 u )

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u= atomic mass unit). The binding energy of .2He^(4) is (mass of helium nucleus =4.0015 u )

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u= atomic mass unit). The binding energy of ._(2)He^(4) is (mass of helium nucleus =4.0015 u )

If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for ._(4)Be^9 (mass=9.012 amu) would be-

The mass of a proton is 1.00816 u and that of a neutron is 1.00902 u. If the mass of a deuterium nucleus (._1H^2) is 2.01479 u, then what will be the binding energy of this nucleus ? (1 u = 931.2 MeV)

The atomic mass . _2^4He is 4.0026 u and the atomic mass of ._1^1H is 1.0078 u . Using atomic mass units instead of kilograms, obtain the binding energy of ._2^4He nucleus.

The atomic mass . _2^4He is 4.0026 u and the atomic mass of ._1^1H is 1.0078 u . Using atomic mass units instead of kilograms, obtain the binding energy of ._2^4He nucleus.

Mass of Helium nucleus = 4 . 00015 amu and mass of a proton =1 .0073 amu mass of neutron= 1.0087 amu Calculate the mass defect and energy liberated in formation of He nucleus and also evaluate binding energy of ._(2)He^(4) nucleus.

If the mass of a proton, m_(p)=1.008u mass of a neutron m_(n)=1.009u ,then the binding energy of an alpha -particle of mass 4.003 u will be (Mev) (take 1a.m.u=931MeV)