If in a `Delta ABC`, `(b+c)/11=(c+a)/12=(a+b)/13` implies `cosA/7=cosB/x` then value of `x` is

If in a Delta ABC,(b+c)/(11)=(c+a)/(12)=(a+b)/(13) implies (cos A)/(7)=(cos B)/(x) then value of x is

If in DeltaABC , (b+c)/(11)=(c+a)/(12)=(a+b)/(13) , then cosA equals :

If in a triangle ABC , (b+c)/11=(c+a)/12=(a+b)/13 then cosA is equal to

If in a triangle ABC , (b+c)/11=(c+a)/12=(a+b)/13 then cosA is equal to

In a triangle ABC , if (b+c)/(11)=(c+a)/(12)=(a+b)/(13) , then cos A=

In DeltaABC, (b+c)/(11) = (c+a)/(12)=(a+b)/(13) , prove that: cosA:cosB:cosC=?

With usual notation , if in triangle ABC, (b + c)/11 = (c + a)/12 = (a + b)/13 , then cos A : cos B : cos C =

With usual notatins, if in a Delta ABC,(b+c)/(11)=(c+a)/(12) =(a+b)/(13), then prove that (cos A)/(7) =(cos B)/(19) =(cos C)/(25).

With usual notatins, if in a Delta ABC,(b+c)/(11)=(c+a)/(12) =(a+b)/(13), then prove that (cos A)/(7) =(cos B)/(19) =(cos C)/(25).