find maximum height reached by small mass m in fig 4E.24

A mass of 10 g moving horizontally with a velocity of 100 m/s, strikes a pendulum bob of mass 10 y. The two masses strike together. The maximum height reached by the system now is g = 10 m//s) :

A ball is thrown vertically upwards with a velocity of 4.9m/s Find (i) the maximum height reached by the ball (ii) time taken to reach the maximum height

A stone is thrown vertically upward with a speed of 28 m/s. (a) Find the maximum height reached by the stone. (b)Find its velocity one second before it reaches the maximum height.

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of 20 m//s (take g= 10 m//s^(2) ).

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of 20 m//s (take g= 10 m//s^(2) ).

A sphere of mass m collides against a pendulum of mass m with horizontal velocity upsilon_90) . (i) Calculate the maximum height reached by the pendulum if the masses scatter elastically along the line of initial motion, (ii) What is the maximum height reached by the pendulum if the two masses stick together ?

Two particles of equal mass are projected simultaneously with speeds 20 m//s end 10sqrt(3)m//s as shown in figure. Find the maximum height reached by the centre of mass of the particles