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If n is an odd number greater than 1, th...

If n is an odd number greater than 1, then `n(n^(2)-1)` is

A

divisible by 96 always

B

divisible by 48 always

C

divisible by 24 always

D

None of these

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The correct Answer is:
To solve the problem, we need to analyze the expression \( n(n^2 - 1) \) where \( n \) is an odd number greater than 1. ### Step-by-Step Solution: 1. **Understanding the Expression**: The expression can be rewritten using the difference of squares: \[ n(n^2 - 1) = n(n - 1)(n + 1) \] Here, \( n - 1 \) and \( n + 1 \) are two consecutive even numbers since \( n \) is odd. 2. **Identifying Even Numbers**: Since \( n \) is odd, both \( n - 1 \) and \( n + 1 \) are even. Therefore, the product \( n(n - 1)(n + 1) \) will always include at least two even numbers. 3. **Finding the Factors**: The product of two consecutive even numbers is divisible by 4. Therefore, we can conclude: \[ (n - 1)(n + 1) \text{ is divisible by } 4 \] 4. **Considering the Odd Factor**: The odd number \( n \) does not contribute any additional factors of 2, but since we have two even numbers, we can conclude that the entire expression \( n(n^2 - 1) \) is divisible by: \[ 4 \times n \] 5. **Finding Divisibility by 8**: Among the two even numbers \( n - 1 \) and \( n + 1 \), one of them is divisible by 4 (since every second even number is divisible by 4). Thus, we can conclude that: \[ n(n - 1)(n + 1) \text{ is divisible by } 8 \] 6. **Final Check for Divisibility by 24**: Now we need to check if \( n(n - 1)(n + 1) \) is divisible by 3. Since \( n \) is odd, it cannot be divisible by 3, but one of \( n - 1 \) or \( n + 1 \) must be divisible by 3 (as they are consecutive integers). Therefore, we can conclude that: \[ n(n^2 - 1) \text{ is divisible by } 3 \] 7. **Combining the Results**: Since we have established that \( n(n^2 - 1) \) is divisible by: - \( 8 \) (from the even numbers) - \( 3 \) (from the consecutive integers) We can conclude that: \[ n(n^2 - 1) \text{ is divisible by } 24 \] ### Conclusion: Thus, if \( n \) is an odd number greater than 1, then \( n(n^2 - 1) \) is divisible by 24.
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ARIHANT SSC-NUMBER SYSTEM-HIGHER SKILL LEVEL QUESTIONS
  1. If n is an odd number greater than 1, then n(n^(2)-1) is

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  2. Find the sum of first 25 natural numbers.

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  3. Findd the sum of the squares of first 35 natural numbers.

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  4. Find the sum of the cubes of first 15 natural numbers.

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  5. Find the sum of first 37 odd numbers.

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  6. Find the sum of first 84 even numbers.

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  7. Sum of first 15 multiples of 8 is

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  8. The product of four consecutive natural numbers plus one is

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  9. Find the unit digit in the product of (268xx539xx826xx102).

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  10. Find the unit digit in the product of (4326xx5321).

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  11. What is the unit digit of in (6817)^(754)?

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  12. What is the unit digit in

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  13. Find the last two-digits of 15xx37xx63xx51xx97xx17 (a)35 (b) 45 (c) 5...

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  14. How many rational numbers are there between 1 and 1000?

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  15. The sum of 5 consecutive even numbers A,B,C,D and E is 130. What is th...

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  16. The sum of the five consecutive numbers is equal to 170. What is the p...

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  17. Which of the following numbers always divides the difference between ...

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  18. A number divided by 56 gives 9 as remainder. If the same number is div...

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  19. [ On dividing a certain number by 357 ,the remainder is 39. On dividin...

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  20. A number when divided by 5 leaves the remainder 3. What is the rema...

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  21. In doing a question of division with zero remainder, a candidate to...

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