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2/3 is a rational number whereas sqrt2/...

2/3 is a rational number whereas `sqrt2/sqrte` is

A

also a rational number

B

an irrational number

C

not a number

D

a natural periodic number

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AI Generated Solution

The correct Answer is:
To determine whether \( \frac{\sqrt{2}}{\sqrt{3}} \) is a rational number or an irrational number, we will follow these steps: ### Step 1: Understand Rational and Irrational Numbers A rational number can be expressed in the form \( \frac{p}{q} \), where \( p \) and \( q \) are integers and \( q \neq 0 \). An irrational number cannot be expressed in this form. **Hint:** Remember that rational numbers can be written as fractions, while irrational numbers cannot. ### Step 2: Analyze the Components We have \( \sqrt{2} \) and \( \sqrt{3} \). We need to determine if these square roots are rational or irrational. **Hint:** Check if the numbers under the square roots are perfect squares. ### Step 3: Determine the Nature of \( \sqrt{2} \) and \( \sqrt{3} \) - \( \sqrt{2} \) is not a perfect square, and it cannot be expressed as a fraction of two integers. Therefore, \( \sqrt{2} \) is an irrational number. - Similarly, \( \sqrt{3} \) is also not a perfect square and cannot be expressed as a fraction of two integers. Thus, \( \sqrt{3} \) is also an irrational number. **Hint:** Recall that square roots of non-perfect squares are always irrational. ### Step 4: Analyze the Fraction \( \frac{\sqrt{2}}{\sqrt{3}} \) Now we consider the fraction \( \frac{\sqrt{2}}{\sqrt{3}} \). Since both the numerator and the denominator are irrational, we need to check if their ratio can be rational. **Hint:** Think about the properties of the division of irrational numbers. ### Step 5: Conclusion The ratio of two irrational numbers can be either rational or irrational. However, in this case, \( \frac{\sqrt{2}}{\sqrt{3}} \) does not simplify to a fraction of two integers. Therefore, it remains irrational. Thus, we conclude that \( \frac{\sqrt{2}}{\sqrt{3}} \) is an irrational number. **Final Answer:** \( \frac{\sqrt{2}}{\sqrt{3}} \) is an irrational number.
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