What least number must be added to 1057 to get a number exactly divisible by 23?

Options

A. 1
B. 3
C. 2
D. 4

Answer

To find the least number that must be added to 1057 to make it exactly divisible by 23, we can follow these steps:

### Step 1: Divide 1057 by 23
First, we need to perform the division of 1057 by 23 to find out how many times 23 fits into 1057 and what the remainder is.

\[ 1057 \div 23 = 45 \quad \text{(approximately)} \]

### Step 2: Calculate the product of the quotient and the divisor
Next, we multiply the quotient (45) by the divisor (23) to find the largest multiple of 23 that is less than or equal to 1057.

\[ 23 \times 45 = 1035 \]

### Step 3: Find the remainder
Now, we find the remainder when we subtract this product from 1057.

\[ 1057 - 1035 = 22 \]

### Step 4: Calculate the least number to add
To find the least number that must be added to 1057 to make it divisible by 23, we subtract the remainder from 23.

\[ 23 - 22 = 1 \]

### Conclusion
Thus, the least number that must be added to 1057 to make it exactly divisible by 23 is **1**.

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