Home
Class 14
MATHS
(16)/(23) xx ( 47)/( 288) xx ( 92)/( 141...

`(16)/(23) xx ( 47)/( 288) xx ( 92)/( 141) = ?`

A

`(4)/( 27)`

B

`( 2)/( 27)`

C

`( 2)/( 29)`

D

`( 3)/( 28)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \((16/23) \times (47/288) \times (92/141)\), we will follow these steps: ### Step 1: Write the expression clearly We start with the expression: \[ \frac{16}{23} \times \frac{47}{288} \times \frac{92}{141} \] ### Step 2: Multiply the numerators and denominators We can multiply the numerators together and the denominators together: \[ \frac{16 \times 47 \times 92}{23 \times 288 \times 141} \] ### Step 3: Simplify the fractions Now we will simplify the fractions step by step. #### Step 3.1: Simplify \(92\) and \(23\) Notice that \(92\) can be divided by \(23\): \[ 92 \div 23 = 4 \quad \text{(since \(23 \times 4 = 92\))} \] So, we can rewrite the expression: \[ \frac{16 \times 47 \times 4}{1 \times 288 \times 141} \] #### Step 3.2: Simplify \(16\) and \(288\) Next, we can simplify \(16\) and \(288\): \[ 288 \div 16 = 18 \quad \text{(since \(16 \times 18 = 288\))} \] So, we rewrite the expression: \[ \frac{1 \times 47 \times 4}{1 \times 18 \times 141} \] #### Step 3.3: Simplify \(47\) and \(141\) Next, we simplify \(47\) and \(141\): \[ 141 \div 47 = 3 \quad \text{(since \(47 \times 3 = 141\))} \] So, we rewrite the expression: \[ \frac{1 \times 1 \times 4}{1 \times 18 \times 3} \] ### Step 4: Final multiplication Now we have: \[ \frac{4}{54} \] We can simplify this further: \[ \frac{4}{54} = \frac{2}{27} \quad \text{(dividing both numerator and denominator by 2)} \] ### Final Answer Thus, the final answer is: \[ \frac{2}{27} \] ---
Promotional Banner

Topper's Solved these Questions

  • SIMPLE AND DECIMAL FRACTIONS

    ARIHANT SSC|Exercise HIGHER SKILL LEVEL QUESTIONS|17 Videos
  • SIMPLE AND DECIMAL FRACTIONS

    ARIHANT SSC|Exercise HIGHER SKILL LEVEL QUESTIONS|17 Videos
  • SET THEORY

    ARIHANT SSC|Exercise EXERCISE - 15 (LEVEL -1)|29 Videos
  • SIMPLE INTEREST

    ARIHANT SSC|Exercise (EXERCISE-C)(HIGHER SKILL LEVEL QUESTION)|16 Videos

Similar Questions

Explore conceptually related problems

30 xx (-23)+ 30xx14 = ?

(-23)xx(42)=(-42)xx _____

(-27) xx (-16) +(-27) xx (-14) = ?

(16)^(0.16) xx (16)^(0.04) xx (2)^(0.2) is equal to :

Use convenient groupings and find the values of (i) 18 xx (-27) xx 30 (ii) (-8) xx (-63) xx 9 (iii) (-17) xx (-23) xx 41 " " (iv) (-51) xx (-47) xx (-19)

Evaluate: ((0. 43) ^(3) + (1. 47) ^(3) + (1.1) ^(3) - 3 xx 0. 43 xx 1 . 47 xx 1.1)/(( ( 0. 43) ^(2) + (1. 47) ^(2) + (1.1) ^(2) -0. 43 xx 1. 43)- 0. 43 xx 1.1 - 1.47 xx 1.1)