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(sqrt5+sqrt3)/(sqrt5-sqrt3)=...

`(sqrt5+sqrt3)/(sqrt5-sqrt3)=`

Text Solution

Verified by Experts

The correct Answer is:
`4+sqrt15`
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Rationalise the denominator of the following (i) 2/(3sqrt3) , (ii) sqrt40/sqrt3 ,(iii) (3+sqrt2)/(4sqrt2) (iv) 16/(sqrt41-5) ,(v) (2+sqrt3)/(2-sqrt3) , (vi) sqrt6/(sqrt2+sqrt3) (vii) (sqrt3+sqrt2)/(sqrt3-sqrt2) ,(viii) (3sqrt5+sqrt3)/(sqrt5-sqrt3) , (ix) (4sqrt3+5sqrt2)/(sqrt48+sqrt18)

2/(sqrt5 - sqrt3)

(sqrt3-sqrt5)(sqrt5+sqrt3)

Simplify (sqrt5 - sqrt3)(sqrt5 + sqrt 3)

(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))+(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3))

simplify (sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))-(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3))

If 2sqrt(x)=(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))-(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3)), then the value of x is :