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If 289=17^(x/5), then x = ?...

If `289=17^(x/5)`, then x = ?

A

16

B

2

C

10

D

`2/5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( 289 = 17^{(x/5)} \), we can follow these steps: ### Step 1: Rewrite 289 as a power of 17 We know that \( 289 \) can be expressed as \( 17^2 \). Therefore, we can rewrite the equation as: \[ 17^2 = 17^{(x/5)} \] ### Step 2: Set the exponents equal to each other Since the bases are the same (both are 17), we can set the exponents equal to each other: \[ 2 = \frac{x}{5} \] ### Step 3: Solve for \( x \) To solve for \( x \), we can multiply both sides of the equation by 5: \[ x = 2 \times 5 \] \[ x = 10 \] ### Final Answer Thus, the value of \( x \) is: \[ \boxed{10} \] ---
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