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[P^((b-c))]^(b+c)*[P^((c-a))]^(c+a)*[P^(...

`[P^((b-c))]^(b+c)*[P^((c-a))]^(c+a)*[P^((a-b))]^((a+b))=?`

A

0

B

`p^(abc)`

C

1

D

`p^(a+b+c)`

Text Solution

Verified by Experts

The correct Answer is:
C
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