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In the afternoon , a student read 100 pa...

In the afternoon , a student read 100 pages at the rate of 60 pages/h . In the evening , when she was tired she read 100 more pages at the rate of 40 pages/h . What was her average rate of reading, in pages per hour ?

A

48

B

50

C

60

D

70

Text Solution

AI Generated Solution

The correct Answer is:
To find the average rate of reading, we need to determine the total number of pages read and the total time spent reading. ### Step 1: Calculate the time spent reading in the afternoon The student read 100 pages at a rate of 60 pages per hour. \[ \text{Time in afternoon} = \frac{\text{Pages}}{\text{Rate}} = \frac{100 \text{ pages}}{60 \text{ pages/hour}} = \frac{100}{60} \text{ hours} = \frac{5}{3} \text{ hours} \approx 1.67 \text{ hours} \] ### Step 2: Calculate the time spent reading in the evening The student read another 100 pages at a rate of 40 pages per hour. \[ \text{Time in evening} = \frac{\text{Pages}}{\text{Rate}} = \frac{100 \text{ pages}}{40 \text{ pages/hour}} = \frac{100}{40} \text{ hours} = 2.5 \text{ hours} \] ### Step 3: Calculate the total time spent reading Now, we add the time spent in the afternoon and the evening: \[ \text{Total time} = \text{Time in afternoon} + \text{Time in evening} = \frac{5}{3} \text{ hours} + 2.5 \text{ hours} \] To add these, convert 2.5 hours into a fraction: \[ 2.5 \text{ hours} = \frac{5}{2} \text{ hours} \] Now, find a common denominator (which is 6): \[ \frac{5}{3} = \frac{10}{6}, \quad \frac{5}{2} = \frac{15}{6} \] So, \[ \text{Total time} = \frac{10}{6} + \frac{15}{6} = \frac{25}{6} \text{ hours} \] ### Step 4: Calculate the total number of pages read The total number of pages read is: \[ \text{Total pages} = 100 \text{ pages (afternoon)} + 100 \text{ pages (evening)} = 200 \text{ pages} \] ### Step 5: Calculate the average rate of reading The average rate of reading is given by: \[ \text{Average rate} = \frac{\text{Total pages}}{\text{Total time}} = \frac{200 \text{ pages}}{\frac{25}{6} \text{ hours}} = 200 \times \frac{6}{25} = \frac{1200}{25} = 48 \text{ pages/hour} \] ### Final Answer The average rate of reading is **48 pages per hour**. ---
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