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P,Q and R hire a meadow for X2920. P put...

P,Q and R hire a meadow for X2920. P puts 10 cows for 20 days, Q puts 30 cows for 8 days and R puts 16 cows for 9 days. Find the rent paid by R.

A

X 735

B

X 820

C

X 575

D

X 720

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The correct Answer is:
To find the rent paid by R, we will follow these steps: ### Step 1: Calculate the total work done by each partner We need to calculate the work done by each partner in terms of cow-days, which is the product of the number of cows and the number of days they were kept. - **For P**: \[ \text{Work by P} = 10 \text{ cows} \times 20 \text{ days} = 200 \text{ cow-days} \] - **For Q**: \[ \text{Work by Q} = 30 \text{ cows} \times 8 \text{ days} = 240 \text{ cow-days} \] - **For R**: \[ \text{Work by R} = 16 \text{ cows} \times 9 \text{ days} = 144 \text{ cow-days} \] ### Step 2: Find the ratio of work done by P, Q, and R Now, we will express the work done by each partner in a ratio: \[ \text{Ratio} = P : Q : R = 200 : 240 : 144 \] ### Step 3: Simplify the ratio To simplify the ratio, we can divide each term by the greatest common divisor (GCD). The GCD of 200, 240, and 144 is 16. \[ \text{Simplified Ratio} = \frac{200}{16} : \frac{240}{16} : \frac{144}{16} = 12.5 : 15 : 9 \] To avoid fractions, we can multiply through by 2: \[ \text{Ratio} = 25 : 30 : 18 \] ### Step 4: Calculate the total parts Now, we will add the parts of the ratio: \[ \text{Total parts} = 25 + 30 + 18 = 73 \] ### Step 5: Calculate R's share of the rent The total rent is X2920. We need to find R's share based on the ratio: \[ \text{R's share} = \frac{\text{R's part}}{\text{Total parts}} \times \text{Total Rent} \] \[ \text{R's share} = \frac{18}{73} \times 2920 \] ### Step 6: Perform the calculation Calculating R's share: \[ \text{R's share} = \frac{18 \times 2920}{73} \] Calculating \( \frac{2920}{73} \): \[ \frac{2920}{73} = 40 \] Now, multiplying by 18: \[ \text{R's share} = 40 \times 18 = 720 \] ### Final Answer Thus, the rent paid by R is **X720**. ---
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