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A man started 20 min late and travel...

A man started 20 min late and traveling at a speed of ` 1 (1)/(2)` times of his usual speed reaches his office in times the time taken by the man to reaches his office in time the time taken by the man to reach his office at his usual speed is

A

40 min

B

1 h 20 min

C

1 h

D

30 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's denote the following: - Let the usual speed of the man be \( S \). - Let the usual time taken to reach the office be \( T \). ### Step 1: Understand the relationship between speed, time, and distance The distance to the office can be expressed as: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Thus, the distance to the office is: \[ D = S \times T \] ### Step 2: Determine the current speed of the man The man is traveling at a speed of \( 1 \frac{1}{2} \) times his usual speed. This can be expressed as: \[ \text{Current Speed} = \frac{3}{2} S \] ### Step 3: Calculate the time taken to reach the office when late Since the man started 20 minutes late, let’s denote the time taken to reach the office at the current speed as \( T' \). According to the problem, he reaches the office in the same time he would have taken at his usual speed if he had not been late, which is \( T \). ### Step 4: Set up the equation for the time taken at current speed Using the formula for distance, we can express the time taken at the current speed: \[ D = \text{Current Speed} \times T' \] Substituting the values we have: \[ S \times T = \left(\frac{3}{2} S\right) \times (T - \frac{1}{3}) \quad \text{(since he is 20 minutes late, which is } \frac{1}{3} \text{ hours)} \] ### Step 5: Simplify the equation Cancelling \( S \) from both sides (assuming \( S \neq 0 \)): \[ T = \frac{3}{2} (T - \frac{1}{3}) \] Now, distribute \( \frac{3}{2} \): \[ T = \frac{3}{2} T - \frac{3}{6} \] This simplifies to: \[ T = \frac{3}{2} T - \frac{1}{2} \] ### Step 6: Rearranging the equation Rearranging gives: \[ T - \frac{3}{2} T = -\frac{1}{2} \] \[ -\frac{1}{2} T = -\frac{1}{2} \] Thus: \[ T = 1 \text{ hour} \] ### Conclusion The usual time taken by the man to reach his office at his usual speed is **60 minutes** or **1 hour**.
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