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The factors of x^2+4y^2+4y-4x y-2x-8 are...

The factors of `x^2+4y^2+4y-4x y-2x-8` are `(x-2y-4)(x-2y+2)` (b) `(x-y+2)(x-4y-4)` `(x+2y-4)(x+2y+2)` (d) none of these

A

`(x-2y-4) (x-2y+ 2)`

B

`(x-y +2) (x-4y+ 4)`

C

`(x-y + 2) (x-4y-4)`

D

`(x+2y-4) (x-2y+2)`

Text Solution

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The correct Answer is:
A
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