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The base of a parallelogram is twice its...

The base of a parallelogram is twice its height. If the area of the parallelogram is 144 sq cm, find its height.

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To solve the problem step by step, we will use the information given about the parallelogram's base, height, and area. ### Step 1: Understand the relationship between base and height We are given that the base (b) of the parallelogram is twice its height (h). This can be expressed mathematically as: \[ b = 2h \] ### Step 2: Write the formula for the area of the parallelogram The area (A) of a parallelogram is calculated using the formula: \[ A = b \times h \] We know from the problem that the area is 144 sq cm. Therefore: \[ 144 = b \times h \] ### Step 3: Substitute the expression for base into the area formula Since we have expressed the base in terms of height, we can substitute \( b = 2h \) into the area formula: \[ 144 = (2h) \times h \] This simplifies to: \[ 144 = 2h^2 \] ### Step 4: Solve for height Now, we need to isolate \( h^2 \) in the equation: \[ 2h^2 = 144 \] To do this, divide both sides by 2: \[ h^2 = \frac{144}{2} \] \[ h^2 = 72 \] ### Step 5: Find the height by taking the square root To find the height \( h \), take the square root of both sides: \[ h = \sqrt{72} \] We can simplify \( \sqrt{72} \) as follows: \[ \sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2} \] ### Conclusion Thus, the height of the parallelogram is: \[ h = 6\sqrt{2} \text{ cm} \] ---
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