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The perimeter of a rectangle having area...

The perimeter of a rectangle having area equal to 144 cm and sides in the ratio`4:9` is

A

52 cm

B

56 cm

C

60 cm

D

64 cm

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The correct Answer is:
To solve the problem, we need to find the perimeter of a rectangle whose area is given as 144 cm² and whose sides are in the ratio of 4:9. ### Step-by-Step Solution: 1. **Understanding the Ratio**: - The sides of the rectangle are in the ratio 4:9. Let's denote the length (L) and breadth (B) of the rectangle as: - Length (L) = 4x - Breadth (B) = 9x - Here, 'x' is a common multiplier. 2. **Using the Area Formula**: - The area (A) of a rectangle is given by the formula: \[ A = L \times B \] - Substituting the expressions for L and B: \[ A = (4x) \times (9x) = 36x^2 \] 3. **Setting Up the Equation**: - We know the area is 144 cm², so we can set up the equation: \[ 36x^2 = 144 \] 4. **Solving for x**: - To find 'x', divide both sides of the equation by 36: \[ x^2 = \frac{144}{36} = 4 \] - Taking the square root of both sides: \[ x = \sqrt{4} = 2 \] 5. **Finding Length and Breadth**: - Now, substitute the value of 'x' back into the expressions for length and breadth: - Length (L) = 4x = 4(2) = 8 cm - Breadth (B) = 9x = 9(2) = 18 cm 6. **Calculating the Perimeter**: - The perimeter (P) of a rectangle is given by the formula: \[ P = 2(L + B) \] - Substituting the values of L and B: \[ P = 2(8 + 18) = 2(26) = 52 \text{ cm} \] ### Final Answer: The perimeter of the rectangle is **52 cm**.
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