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A rectangle has 30 cm as its length and ...

A rectangle has 30 cm as its length and 720 sq cm as its area. Its area is increased to 1 1/4 times its original area 4 by increasing only its length. Its new perimeter is

A

a. 123 cm

B

b. 125 cm

C

c. 119 cm

D

d. 121 cm

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The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Understand the given information We know the following: - Length of the rectangle (L) = 30 cm - Area of the rectangle (A) = 720 sq cm ### Step 2: Calculate the width of the rectangle The area of a rectangle is given by the formula: \[ \text{Area} = \text{Length} \times \text{Width} \] We can rearrange this to find the width (W): \[ W = \frac{A}{L} \] Substituting the known values: \[ W = \frac{720 \text{ sq cm}}{30 \text{ cm}} = 24 \text{ cm} \] ### Step 3: Calculate the new area after increasing it to 1 1/4 times the original area 1 1/4 times the original area can be expressed as: \[ \text{New Area} = \frac{5}{4} \times 720 \text{ sq cm} \] Calculating this gives: \[ \text{New Area} = 900 \text{ sq cm} \] ### Step 4: Set up the equation for the new length Let the new length be \( L' \). Since the width remains unchanged, we can use the area formula again: \[ \text{New Area} = L' \times W \] Substituting the values we have: \[ 900 \text{ sq cm} = L' \times 24 \text{ cm} \] Now, solve for \( L' \): \[ L' = \frac{900 \text{ sq cm}}{24 \text{ cm}} = 37.5 \text{ cm} \] ### Step 5: Calculate the new perimeter The perimeter (P) of a rectangle is given by the formula: \[ P = 2 \times (L + W) \] Substituting the new length and the original width: \[ P = 2 \times (37.5 \text{ cm} + 24 \text{ cm}) \] Calculating this gives: \[ P = 2 \times 61.5 \text{ cm} = 123 \text{ cm} \] ### Final Answer The new perimeter of the rectangle is **123 cm**. ---
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