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Consider the following statements Area o...

Consider the following statements Area of segment of a circle is less than area of its corresponding sector. Distance travelled by a circular Wheel of diameter 2d cm in one revolution is greater than 6d cm. Which of the above statements is/are correct?

A

a. Only I

B

b. Only II

C

c. Both I and II

D

d. neither I nor II

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The correct Answer is:
To solve the problem, we need to analyze the two statements given in the question one by one. ### Step 1: Analyze the first statement **Statement 1:** The area of the segment of a circle is less than the area of its corresponding sector. - **Understanding the terms:** - A **sector** is a portion of a circle defined by two radii and the arc between them. - A **segment** is the area of a circle that is "cut off" from the rest of the circle by a chord. - **Formula for the area of a sector:** \[ \text{Area of sector} = \frac{\theta}{360} \times \pi r^2 \] where \(\theta\) is the angle in degrees and \(r\) is the radius of the circle. - **Formula for the area of a triangle formed by the two radii and the chord:** \[ \text{Area of triangle} = \frac{1}{2} r^2 \sin(\theta) \] - **Formula for the area of the segment:** \[ \text{Area of segment} = \text{Area of sector} - \text{Area of triangle} \] - **Conclusion:** Since the area of the segment is the area of the sector minus the area of the triangle, it follows that: \[ \text{Area of segment} < \text{Area of sector} \] Therefore, **Statement 1 is correct.** ### Step 2: Analyze the second statement **Statement 2:** The distance travelled by a circular wheel of diameter \(2d\) cm in one revolution is greater than \(6d\) cm. - **Understanding the terms:** - The distance travelled in one revolution of a circular wheel is equal to its circumference. - **Formula for the circumference of a circle:** \[ \text{Circumference} = \pi \times \text{diameter} = \pi \times 2d = 2\pi d \] - **Calculating the circumference:** Using the approximate value of \(\pi \approx 3.14\): \[ \text{Circumference} \approx 2 \times 3.14 \times d = 6.28d \] - **Conclusion:** Since \(6.28d\) is greater than \(6d\), we can conclude that: \[ \text{Circumference} > 6d \] Therefore, **Statement 2 is also correct.** ### Final Conclusion Both statements are correct.
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