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A circle of radius 10 cm has an equilate...

A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is

A

`2.5sqrt(3)` cm

B

5 cm

C

`10sqrt(3)` cm

D

None of these

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The correct Answer is:
To find the length of the perpendicular drawn from the center of a circle to any side of an inscribed equilateral triangle, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the radius of the circle**: The radius (R) of the circle is given as 10 cm. 2. **Understand the relationship between the radius and the side of the equilateral triangle**: For an equilateral triangle inscribed in a circle, the relationship between the radius (R) of the circumscribed circle and the side length (A) of the triangle is given by the formula: \[ R = \frac{A}{\sqrt{3}} \] 3. **Rearrange the formula to find the side length (A)**: From the formula, we can express the side length (A) in terms of the radius (R): \[ A = R \cdot \sqrt{3} \] Substituting R = 10 cm: \[ A = 10 \cdot \sqrt{3} \text{ cm} \] 4. **Determine the length of the perpendicular from the center to a side**: The length of the perpendicular (h) from the center of the circle to any side of the triangle can be calculated using the formula: \[ h = \frac{A \cdot \sqrt{3}}{2} \] Substituting A = \(10 \cdot \sqrt{3}\): \[ h = \frac{(10 \cdot \sqrt{3}) \cdot \sqrt{3}}{2} \] Simplifying this: \[ h = \frac{10 \cdot 3}{2} = \frac{30}{2} = 15 \text{ cm} \] 5. **Find the perpendicular distance from the center to the side**: However, we need to find the perpendicular distance from the center to the side of the triangle. The correct formula for the height (h) from the center of the triangle to a side is: \[ h = \frac{R \cdot \sqrt{3}}{2} \] Substituting R = 10 cm: \[ h = \frac{10 \cdot \sqrt{3}}{2} = 5\sqrt{3} \text{ cm} \] ### Final Answer: The length of the perpendicular drawn from the center to any side of the triangle is \(5\sqrt{3}\) cm.
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