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If two vertices of a triangle are (5, 4)...

If two vertices of a triangle are (5, 4) and (-2, 4) and centroid is (5, 6), then third vertex is

A

(12, 10)

B

(10, 12)

C

(-10, 12)

D

(12, -10)

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The correct Answer is:
To find the third vertex of the triangle given two vertices and the centroid, we can follow these steps: ### Step 1: Identify the given points We have two vertices of the triangle: - Vertex A (x1, y1) = (5, 4) - Vertex B (x2, y2) = (-2, 4) The coordinates of the centroid (G) are given as: - Centroid G (xg, yg) = (5, 6) ### Step 2: Use the centroid formula The formula for the centroid of a triangle with vertices (x1, y1), (x2, y2), and (x3, y3) is: \[ x_g = \frac{x_1 + x_2 + x_3}{3} \] \[ y_g = \frac{y_1 + y_2 + y_3}{3} \] ### Step 3: Set up the equations Let the coordinates of the third vertex be (x3, y3) = (a, b). Using the centroid formulas, we can set up the following equations: 1. For the x-coordinate: \[ 5 = \frac{5 + (-2) + a}{3} \] 2. For the y-coordinate: \[ 6 = \frac{4 + 4 + b}{3} \] ### Step 4: Solve for 'a' (the x-coordinate of the third vertex) From the first equation: \[ 5 = \frac{5 - 2 + a}{3} \] \[ 5 = \frac{3 + a}{3} \] Multiplying both sides by 3: \[ 15 = 3 + a \] Subtracting 3 from both sides: \[ a = 12 \] ### Step 5: Solve for 'b' (the y-coordinate of the third vertex) From the second equation: \[ 6 = \frac{4 + 4 + b}{3} \] \[ 6 = \frac{8 + b}{3} \] Multiplying both sides by 3: \[ 18 = 8 + b \] Subtracting 8 from both sides: \[ b = 10 \] ### Step 6: State the third vertex Thus, the coordinates of the third vertex are: \[ \text{Third vertex} = (a, b) = (12, 10) \] ### Final Answer The third vertex of the triangle is (12, 10). ---
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