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A point C divides the line AC, where A(1...

A point C divides the line AC, where A(1, 3) and B(2, 7) in the ratio of `3:4` . The coordinates of C are

A

`(5/3, 5)`

B

`(-2, -9)`

C

`(3/5, 5)`

D

`(10/7 , 33/7)`

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The correct Answer is:
To find the coordinates of point C that divides the line segment AB in the ratio 3:4, we can use the section formula. The coordinates of points A and B are given as A(1, 3) and B(2, 7). ### Step-by-Step Solution: 1. **Identify the coordinates of points A and B:** - A = (x1, y1) = (1, 3) - B = (x2, y2) = (2, 7) 2. **Identify the ratio in which point C divides the line segment AB:** - The ratio is given as m:n = 3:4, where m = 3 and n = 4. 3. **Use the section formula to find the coordinates of point C:** - The section formula for the coordinates of point C (x, y) that divides the line segment joining points A and B in the ratio m:n is given by: \[ C\left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \] 4. **Substitute the values into the formula:** - For the x-coordinate: \[ x = \frac{3 \cdot 2 + 4 \cdot 1}{3 + 4} = \frac{6 + 4}{7} = \frac{10}{7} \] - For the y-coordinate: \[ y = \frac{3 \cdot 7 + 4 \cdot 3}{3 + 4} = \frac{21 + 12}{7} = \frac{33}{7} \] 5. **Combine the results to find the coordinates of point C:** - Therefore, the coordinates of point C are: \[ C\left( \frac{10}{7}, \frac{33}{7} \right) \] ### Final Answer: The coordinates of point C are \( C\left( \frac{10}{7}, \frac{33}{7} \right) \). ---
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