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Are the points (1, 7), (4, 2), (-1, -1) ...

Are the points (1, 7), (4, 2), (-1, -1) and (-4, 4) vertices of a square ? If yes, what is the length of the side of square ?

A

`34`

B

`sqrt34`

C

`-34`

D

`68`

Text Solution

AI Generated Solution

The correct Answer is:
To determine if the points (1, 7), (4, 2), (-1, -1), and (-4, 4) are the vertices of a square, we will follow these steps: ### Step 1: Identify the Points Let: - A = (1, 7) - B = (4, 2) - C = (-1, -1) - D = (-4, 4) ### Step 2: Calculate the Distances Between Each Pair of Points We will calculate the distances between each pair of adjacent points (AB, BC, CD, DA) and check if they are equal. **Distance Formula:** The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step 3: Calculate AB Using points A and B: \[ AB = \sqrt{(4 - 1)^2 + (2 - 7)^2} = \sqrt{(3)^2 + (-5)^2} = \sqrt{9 + 25} = \sqrt{34} \] ### Step 4: Calculate BC Using points B and C: \[ BC = \sqrt{(-1 - 4)^2 + (-1 - 2)^2} = \sqrt{(-5)^2 + (-3)^2} = \sqrt{25 + 9} = \sqrt{34} \] ### Step 5: Calculate CD Using points C and D: \[ CD = \sqrt{(-4 - (-1))^2 + (4 - (-1))^2} = \sqrt{(-3)^2 + (5)^2} = \sqrt{9 + 25} = \sqrt{34} \] ### Step 6: Calculate DA Using points D and A: \[ DA = \sqrt{(1 - (-4))^2 + (7 - 4)^2} = \sqrt{(5)^2 + (3)^2} = \sqrt{25 + 9} = \sqrt{34} \] ### Step 7: Compare the Distances We have: - \(AB = \sqrt{34}\) - \(BC = \sqrt{34}\) - \(CD = \sqrt{34}\) - \(DA = \sqrt{34}\) Since all four sides are equal, we can conclude that the points form a square. ### Step 8: Determine the Length of the Side of the Square The length of the side of the square is: \[ \text{Length of side} = \sqrt{34} \] ### Conclusion Yes, the points (1, 7), (4, 2), (-1, -1), and (-4, 4) are the vertices of a square, and the length of the side of the square is \(\sqrt{34}\). ---
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