The equatioin of the image of the circle `x^2+y^2+016 x-24 y+183=0` in the line mirror `4x+7y+13=0` is: a.`x^2+y^2+32 x-4y+235=0` b.`x^2+y^2+32 x+4y-235=0` c.`x^2+y^2+32 x-4y-235=0` d.`x^2+y^2+32 x+4y+235=0`

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is :

The equation of the image ofthe circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

Find the image of the circle x^(2)+y^(2)-2x+4y-4=0 in the line 2x-3y+5=0

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 in the mirror 4x+7y+13=0 is x^(2)+y^(2)+32x-4y+235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x-4y-235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x+4y+235=0

Equation of the diameter of the circle x^(2)+y^(2)-2x+4y=0 which passes through the origin is x+2y=0 b.x-2y=0 c.2x+y=0 d.2x-y=0

Suppose a x+b y+c=0 , where a ,ba n dc are in A P be normal to a family of circles. The equation of the circle of the family intersecting the circle x^2+y^2-4x-4y-1=0 orthogonally is (a)x^2+y^2-2x+4y-3=0 (b)x^2+y^2-2x+4y+3=0 (c)x^2+y^2+2x+4y+3=0 (d) x^2+y^2+2x-4y+3=0

The point of tangency of the circles x^(2)+y^(2)-2x-4y=0 and x^(2)+y^(2)-8y-4=0 is

Let the equation of circle is x^(2) + y^(2) - 6x - 4y + 9 = 0 . Then the line 4x + 3y - 8 = 0 is a