Show that any number of the form ` 6^(n)` , where ` n ne N` can never and with the digit 0.

Show that any number of the form 4^(n),n ne N can never end with the digit 0.

Any number of the form 4^(n), n != N can never end with the digit

Consider the numbers of the form 4^n where n is a natural number. Check whether there is any value of n for which 4^n ends with zero?

Consider the numbers of the form 4^n where n is a natural number. Check whether there is any value of n for which 4^n ends with zero?

Consider the numbers of the form 4^n where n is a natural number. Check whether there is any value of n for which 4^n ends with zero?

Consider the numbers of the form 4^n where n is a natural number. Check whether there is any value of n for which 4^n ends with zero?

A number is selected from 4 digit numbers of the form 5n+2 where n belongs to N containing exactly one digit as 7 . Find the probability that number when divided by 5 leaves remainder 2.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.