A straight line through the origin `O` meets the parallel lines `4x+2y=9` and `2x+y+6=0` at points `P` and `Q` respectively. Then the point `O` divides the segement `P Q` in the ratio (1) `1:2` (2) `3:4` (3) `2:1` (4) `4:3`

A straight line through the origin 'O' meets the parallel lines 4x+2y=9 and 2x+y=-6 at points P and Q respectively.Then the point 'divides the segment PQ in the ratio

A straight line through the origin o meets the parallel lines 4x+2y= 9 and 2x +y+ 6=0 points P and Q respectively. Then the point o divides the segment PQ in the ratio: : (A) 1:2 (B) 3:2 (C) 2:1 D) 4:3

A straight line through the point A(1,1) meets the parallel lines 4x+2y=9&2x+y+6=0 at points P and Q respectively.Then the point A divides the segment PQ in the ratio:

A straight line through origin O meets the lines 3y=10-4x and 8x+6y+5=0 at point A and B respectively. Then , O divides the degment AB in the ratio.

A straight line L passing through the point P(-2,-3) cuts the lines, x + 3y = 9 and x+y+1=0 at Q and R respectively. If (PQ) (PR) = 20 then the slope line L can be (A) 4 (B) 1 (C) 2 (D) 3

A line through point A(1,3) and parallel to the line x-y+1 = 0 meets the line 2x-3y + 9 = 0 at point P. Find distance AP without finding point P.

A straight-line L through the origin meets the lines x+y=1 and x+y=3 at P and Q respectively. Through P and Q two straight lines L_(1) and L_(2) are drawn, parallel to 2x-y=5 and 3x+y=5 , respectively. Lines L_(1) and L_(2) intersect at R, show that the locus of R as L varies, is a straight line

A straight line L.through the origin meets the lines x+y=1 and x+y=3 at P and Q respectively.Through P and Q two straight lines L_(1), and L_(2) are drawn,parallel to 2x-y-5 and 3x+y5 respectively.Lines L_(1) and L_(2) intersect at R.Locus of R, as L varies, is