The solutioni of `x+y+z=7,x+2y+3z=16,x+3y+4z=22` is

The solution of 2x+y+z=1,x-2y-3z=1,3x+2y+4z=5 is

2x-y+z=6,x+2y+3z=3,3x+y-z=4

If (x,y,z) is the solution of the equations 4x + y = 7 3y + 4z = 5 5x + 3z = 2 Then the value of x + y + z equals

x+y+z=1 x-2y+3z=2 5x-3y+z=3

The values of x, y, z for the equations x-y+z=1, 2x-y=1, 3x+3y-4z=2 are

The system of equations x+y+z=6, x+2y+3z=14, x+4y=7z=30 has

The system of equations x +2y+3z=1, x-y+4z=0, 2x+y+7z=1 has