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A body projected along an inclined plane...

A body projected along an inclined plane of angle of inclination 300 stops after covering a distance `x_(1)`. The same body projected with the same speed stops after covering a distance `x_(2)` when the angle of inclination of the inclined plane is increased to `60^(@)` the ratio of `x_(1)//lx_(2)` is

A

`sqrt(2)`

B

2

C

`sqrt(3)`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C

Hence applying `v^(2)-u^(2)=2as`
In first case`0-u^(2)=2(-gsin30^@)x_(1)`
or `u^(2)=gx_(1)`
In second case`0-u^(2)=2(-gsin60^@)x_(2)`
or `u^(2)=sqrt(3)gx_(2)`
or `gx_(1)=sqrt(3)gx_(2)`
or `x_(1)/x_(2)=sqrt(3)`
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