A projectile of mass m is fired with vel...

A projectile of mass m is fired with velocity v from a point P at `theta` = 45°. Neglecting air friction, the magnitude of change of momentum between the leaving pt. P and arriving pt. Q is :

`(mv)/sqrt(2)`

2mv

`1/2mv`

`sqrt(2)mv`

Text Solution

Verified by Experts

The correct Answer is:

`P_(1y)=mvsintheta,p_(2y)=-mvsintheta.` As `theta=45^@`
`:. |Deltap_(y)|=2mvsintheta=2mvxx1/sqrt(2)=sqrt(2)mv`

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