If a particle is at rest with three velocities of 14 units, 16 units and 26 units on it, then the angle between the directions of the two smaller velocities is :

Options

A. 30°
B. 60°
C. 120°
D. 150°

Answer

B

Explanation

As the particle is at rest then
`|R|=sqrt(A^(2) + B^(2)+2ABcostheta)`
`(26)^(2)=(14)^(2) + (16)^(2) + 2xx16 xx14costheta`
On solving `costheta=1/2` or `theta=60^@`