The equation of projectile is y=sqrt(3)-...

The equation of projectile is `y=sqrt(3)-g/2x^(2)` , the angle of its projection is :

`pi/2`

zero

`theta=tan^(-1)sqrt(3)`

`theta=tan^(-1)(1/sqrt(3))`

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Verified by Experts

The correct Answer is:

The equation of trajectory of parabolic path is
`y=xtantheta -(g/(2u^(2)cos^(2)theta)).x^(2)`compairing this with `y=sqrt(3x)-g x^(2)/2`
we have `tantheta=sqrt(3)`

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