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A projectile is projected with initial v...

A projectile is projected with initial velocity (`6hat(i) + 8hat(j)`) m`s^(-1)` if g = 10 `ms^(-2)` , then horizontal range is :

A

4.8m

B

9.6m

C

19.2m

D

14.0m

Text Solution

Verified by Experts

The correct Answer is:
B
Here `vec(v)=6hati +8hatj`
`:. |v|=sqrt(6^(2)+8^(2))=10ms^(-1)`
Also `vcostheta=6` and `vsintheta=8`
`g=10ms^(-2)`
`:.R=(2vcostheta.vsintheta)/g`
`=(2xx6xx8)/10=9.6m`
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