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A boy playing on the roof of a 10 m high...

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will be ball be at the height of 10 m from the ground ?
`[g=10ms^(-2),sin30^@=1/2,cos30^@=sqrt(3)/2]`

A

8.66 m

B

5.20 m

C

4.33 m

D

2.60 m

Text Solution

Verified by Experts

The correct Answer is:
A
Here `R=(u^(2)sin2theta)/g=((10)^(2)sin60^@)/10`
`5sqrt(3)=8.66m`
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