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A particle is projected at 60° to the ho...

A particle is projected at 60° to the horizontal with a kinetic energy K. The kinetic energy at the highest point is:

A

Zero

B

K/4

C

K/2

D

K

Text Solution

Verified by Experts

The correct Answer is:
B
Here energy at the start `1/2mv^(2)=K`
K.E. at the top `=1/2mv^(2)cos^(2)theta=Kcos^(2)60^@=K/4`
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