A particle moving with constant acceleration of `2m//s^(2)` due west has an initial velocity of 9m/s due east. Find the distance covered in the fifth second of its motion.

A particle moving with constant acceleration of 2m/ s^(2) due west has an initial velocity of 9 m/s due east. Find the distace covered in the fifth second of its motion.

A particle moving with constant acceleration of 2m/ s^(2) due west has an initial velocity of 9 m/s due east. Find the distace covered in the fifth second of its motion.

A particle moving with constant acceleration of 2m/ s^(2) due west has an initial velocity of 9 m/s due east. Find the distace covered in the fifth second of its motion.

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle has an initial velocity of 9m//s due east and a constant acceleration of 2m//s^(2) due west. The distance coverd by the particle in the fifth second of its motion is :

A particle is moving under a constant acceleration of 3m//s^(2) . The initial velocity of the particle is 10m/s. calculate the distance travelled by the particle is 5s and also in th 5th second of its motion.