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C(p)-C(v)=R//J for one mole of the gas. ...

`C_(p)-C_(v)=R//J` for one mole of the gas. If we consider n moles of the gas, the formula becomes:

A

`C_(p)-C_(v)=(R )/(J)`

B

`C_(p)-C_(v)=n.R//J`

C

`C_( r)-C_(v)=(R )/(nJ)`

D

None of the above.

Text Solution

Verified by Experts

The correct Answer is:
A

`C_(p)-C_(v)=(R )/(J)` Here R is gas constant for 1 mole of the gas.
For n moles of the gas each terms on L.H.S and the term on R.H.S. is multiplied by n and hence even for n moles of gas the relation remains the same.
Thus, correct choice is (a).
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