The number of degrees of freedom for molecules of monoatomic gas is

Options

A. `30.1xx10^(23)`
B. `18.01xx10^(23)`
C. `30.1xx10^(21)`
D. None of the above.

Answer

A

Explanation

At N.T.P. each molecule of diatomic gas possesses 5 degress of freedom i.e., f=5
1 mole of the gas contains `N=6.023xx10^(23)` molecules.
`therefore` Total number of degress of freedom =Nf.
`=6 cdot 023xx10^(23)xx5=30cdot115xx10^(23)`
Thus, correct choice is (a).