A reversible Carnot's engine is working between 260 K and 300K. It takes 500 cal of heat from sink. Heat rejected to the source at higher temp. for this refrigerator is:

Options

A. 400 cal
B. 477 cal
C. 377 cal
D. 577 cal.

Answer

D

Explanation

`T_(1)=300 K" "T_(2)=260 K.`
`Q_(2)=500 cal. Q_(1)=?`
Here, for refrigerator also `(Q_(1))/(Q_(2))=(T_(1))/(T_(2))`
` Q_(1)=Q_(2)xx(T_(1))/(T_(2))=500 xx (300)/(260)`
`Q_(1)=576 cdot 9 cal = 577 cal`.
Hence, correct choice is (d).