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Efficiency of engine is eta(1)" at T(1)=...

Efficiency of engine is `eta_(1)" at T_(1)= 200^(@)C` and `eta_(2)" at "T_(1)=0^(@)C and T_(2)=-200 K.` Find the ratio of `(eta_(1))/(eta_(2))` :

A

`1 cdot 00`

B

`0 cdot 577`

C

`0 cdot 721`

D

`0 cdot 34`

Text Solution

Verified by Experts

The correct Answer is:
B
`eta_(1)=1-(273)/(473)=(200)/(473)`
`eta_(2)=1-((-200+273))/(273)=(200)/(273)`
`therefore (eta_(1))/(eta_(2))=(273)/(473)=0 cdot 577`
So, correct choice is (b).
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